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A parabola intersects the x-axis at x = 3 and x = 9.

What is the x-coordinate of the parabola's vertex?

asked
User Schneck
by
8.5k points

2 Answers

5 votes

Answer:

6

Explanation:

This function corresponds to 'even' function, then

in order to calculate the 'x' of the vertex: (3+9)/2=6.

answered
User Bielas
by
8.7k points
0 votes

Answer:

The x-coordinate of the parabola's vertex is 6.

Explanation:

A parabola in the following format:


y = ax^(2) + bx + c

With


\Delta = b^(2) - 4ac

Has the following vertex:


V = (x_(v), y_(v))

In which


x_(v) = -(b)/(2a)


y_(v) = -(\Delta)/(4a)

In this problem, we have that:

A parabola intersects the x-axis at x = 3 and x = 9. This means that the roots are x = 3 and x = 9, and that our parabola is defined by the following equation:


y = (x - 3)(x - 9) = x^(2) - 12x + 27

So


x = 1, b = -12, c = 27


x_(v) = -(b)/(2a) = -(-12)/(2) = 6

The x-coordinate of the parabola's vertex is 6.

answered
User Rourke
by
8.6k points
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