Question

A=2/b+3c ; solve for c

Answer 1

It is straightforward.

Answer is c= a/3 - 2/3b

Answer 2

`c=(a)/(3) +(2)/(3b)`

Explanation:

`a=(2)/(b) +3c`

Solve for x, we need to get 'c' alone

To remove fraction 2/b , we need to subtract 2/b from both sides

`a-(2)/(b)=(2)/(b)-(2)/(b)+3c`

`a-(2)/(b)=3c`

Divide by 3 on both sides

`(a)/(3) +(2)/(3b)=c`