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What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)​

What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)​
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What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)​

asked
User Nicq
by
7.6k points

2 Answers

3 votes

Answer:

y = -4x - 4

Explanation:

answered
User Carrdelling
by
7.9k points
4 votes
In order for a line to be perpendicular, its slope must be the negative reciprocal of the other line. We’re solving for the b part of y = mx + b

The new line = -4x + b

4 = -4(-2) + b

4 = 8 + b

b = -4

The equation of the line is y = -4x - 4
answered
User Fiz
by
7.1k points
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