Question

Find the maximum potential difference between two parallel conducting plates separated by 1.18 cm of air, given the maximum sustainable electric field strength in air to be 3.0\times 10^6~\text{V/m}3.0×10 ​6 ​​ V/m.

Answer 1

The maximum potential difference between two parallel conducting plates is 35400V

Step-by-step explanation:

The potential difference between two conductive plates is determined by the following formula:

V=E*d Equation (1)

Where,

V: The potential difference in volts (V)

E: The electric field in V/m

d : Distance between the plates (m)

Known data:

`E=3*10^(6) (V)/(m)`

D=1.18cm, 1m=100cm, D=1.18cm*1m/100cm

`d=1.18*10^(-2) m`

We replace the information known in the equation (1):

`V=3*10^(6) *1.18*10^(-2)`

`V=3.54*10^(4)`

V=35400V