Question

the position of an object is given by the equation x = 3.0t^2+1.5t+4.5, where x in meters and t is in seconds. what is the instantaneous acceleration of the object at t = 3.0 s?

Answer 1

6 m/s²

Step-by-step explanation:

`x(t) = 3t^2+1.5t+4.5\\v(t)=(dx)/(dt)=6t + 1.5\\a(t)=(d^2x)/(dt^2)= 6`