Distance formula (3,0) (3,-3)

Question

asked Apr 28, 2020 33.8k views

2 Answers

Simon LG · Answer 1 · 2020-05-02T17:12:09+0000

The formula for distance between two points is:

$\sqrt{(x_(2) -x_(1))^(2) + (y_(2) -y_(1))^(2)}$

In this case:

$x_(2) =3\\x_(1) =3\\y_(2) =-3\\y_(1) =0$

^^^Plug these numbers into the formula for distance like so...

$\sqrt{(3-3)^(2) + (-3-0)^(2)}$

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

$\sqrt{(3-3)^(2) + (-3-0)^(2)}$

3 - 3 = 0

$\sqrt{(0)^(2) + (-3-0)^(2)}$

-3 - 0 = -3

$\sqrt{(0)^(2) + (-3)^(2)}$

Next solve the exponent. Again, you must do this from left to right

$\sqrt{(0)^(2) + (-3)^(2)}$

0² = 0

$\sqrt{0 + (-3)^(2)}$

(-3)² = 9

√((0 + 9))

Now for the addition

√((0+9))

0 + 9 = 9

√9 <<<This can be further simplified to:

3 units

***Remember that the above answers are in terms of units

Hope this helped!

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