Question

Makayla is taking a math course and is working with the perimeter of rectangles. She knows the perimeter and length of her rectangle but wants to solve for the width. Rearrange the following equation for W, where P is the perimeter, L is the length, and W is the width of the rectangle.

P = 2L + 2W

W = 2P − 2L
W = P/ 2-2 times L
W equals the quantity P minus 2 times L all over 2
W = 2P + 2L

Answer 1

`\bf P=2L+2W\implies P-2L=2W\implies \cfrac{P-2L}{2}=W`

Answer 2

Third option:
`W=(P-2L)/(2)`

Explanation:

Knowing that the equation used to calculate that perimeter of the rectangle is:

`P = 2L + 2W`

Where "P" is the perimeter, "L" is the leght and "W" is the width, Makayla can follow these steps in order to solve for "W":

- Subtract
`2L` from both sides of the equation:

`P -2L= 2L + 2W-2L\\\\P-2L=2W`

- Divide both sides of the equation by 2:

`(P-2L)/(2)=(2W)/(2)\\\\W=(P-2L)/(2)`