asked 86.5k views
4 votes
Julie has $3.10 in change in her pocket. If she has only 50 cent and 20 cent pieces and the total number of coins is 11, how many coins of each type does she have?

asked
User Akond
by
8.0k points

1 Answer

4 votes

Answer: 50 cent pieces = qty 3

20 cent pieces = qty 8

Explanation:

Let x represent the 50 cent pieces and y represent the 20 cent pieces. Create a system of equations using the quantity as one equation and the value as the other equation. Use elimination method to solve for one of the variables, then use substitution to solve for the other variable.

x + y = 11 → -20(x + y = 11) → -20x - 20y = -220

.50x + .20y = 3.10 → 100(.50x + .20y = 3.10) → 50x + 20y = 310

30x = 90

x = 3

x + y = 11

3 + y = 11

y = 8

answered
User Scrashdemix
by
8.6k points

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