A car traveling at 50 m/s uniformly accelerates to 60 m/s over an 58 second interval. What is the displacement?

Question

asked Apr 1, 2020 129k views

2 Answers

Axelarge · Answer 1 · 2020-04-03T21:53:09+0000

Step-by-step explanation:

here u = 50m/s

v = 60m/s

t = 58 s

then a = (60-50)/58 m/s2

= 0.17m/s2

now s= ut+1/2at2

so , 50×58+0.5×0.17×(58)^2 m

= 3185.94 m

= 3.18 km

Xorcus · Answer 2 · 2020-04-06T17:51:36+0000

The displacement of 3190 m a car can travel if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.

A car traveling at 50 m⁄s to 60 m⁄s over a 58 second interval the displacement of car is found by using the formula:

s=(1)/(2)(v+u) t

Where,

v is final velocity = 60 m/s

u is initial velocity = 50 m/s

t is time taken = 58 s

s is displacement

Now,

$\Rightarrow s=(1)/(2)(60+50) 58$

$\Rightarrow s=(1)/(2)(110) 58$

$\therefore s=3190 \ m$

Hence, a car travels 3190 m if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.