Question

Given a heat source of 200C and a heat sink of 20C, what is the maximum theoretical efficiency for a Carnot engine? (numerical percentage out of 100 without the % symbol)

Answer 1

Answer : The maximum theoretical efficiency for a Carnot engine is 90.

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used :

`\eta \%=(Q_h-Q_c)/(Q_h)* 100`

where,

`\eta` = efficiency of carnot engine = ?

`Q_h` = heat supplied by hot source = 200 C

`Q_c` = heat supplied by cold source = 20 C

Now put all the given values in this formula, we get :

`\eta \%=(Q_h-Q_c)/(Q_h)* 100`

`\eta \%=(200-20)/(200)* 100`

`\eta \%=90`

Therefore, the maximum theoretical efficiency for a Carnot engine is 90.