Question

5) Find the value of x, given m/PQS = 112°
(10xjo
20​

Answer 1

x=4

Explanation:

we know that

m∠PQS=m∠PQR+m∠RQS

we have

m∠PQS=112°

m∠PQR=72°

m∠RQS=10x

substitute

112°=72°+10x

Solve for x

10x=112°-72°

10x=40

x=4