Question

a ball is thrown vertically upward from the ground with an initial velocity of 60 ft/sec. how high will the ball go?

Answer 1

The ball will go to maximum height of 56.25 meters.

Explanation:

It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec

Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

`h(t)=-16t^2+vt+h`

h = 0

`h(t)=-16t^2+60t`..............(1)

We need to find the maximum height reached by the ball. For maximum height,

`(dh(t))/(dt)=0`

`(d(-16t^2+60t))/(dt)=0`

t = 1.875 seconds

Put the values of t in equation (1). So,

`h(t)=-16(1.875)^2+60(1.875)`

h(t) = 56.25 meters

So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.