Question

You are given a parallel plate capacitor that has plates of area 27 cm^2 which are separated by 0.0100 mm of nylon (dielectric constant x = 3.4). You are told to assume that this capacitor stores 011 mC of charge. Calculate what the applied voltage in kV should be for this capacitor

Answer 1

Applied voltage should be 13.5396 kV

Step-by-step explanation:

The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by

`Q=(K\epsilon _(o) A)/(d)V`

Solving for V we get

`V=(Qd)/(K\epsilon _(o)A)`

thus to store a charge of 0.11mC we solve for V as follows

Applying values we get

`V=(0.11* 10^(-3)* 0.01* 10^(-3))/(27* 10^(-4)* 3.4* 8.85* 10^(-12))`

`\therefore V=13.5396kV`