Question

What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is 5.90 x 10^5 K?

Answer 1

Answer: The average kinetic energy of helium atoms is
`1.222* 10^(-17)J`

Step-by-step explanation:

To calculate the average kinetic energy of the atom, we use the equation:

`K=(3)/(2)kT`

where,

K = average kinetic energy = ?

k = Boltzmann constant =
`1.3807* 10^(-23)J/K`

T = temperature =
`5.9* 10^5K`

Putting values in above equation, we get:

`K=(3)/(2)* 1.3807* 10^(-23)J/K* 5.9* 10^5K\\\\K=1.222* 10^(-17)J`

Hence, the average kinetic energy of helium atoms is
`1.222* 10^(-17)J`