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Write a slope- intercept equation for a line with given characters m=-4/5, passes through (-4,-5)

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User YFeizi
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\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-5})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{4}{5} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{-\cfrac{4}{5}}[x-\stackrel{x_1}{(-4)}]\implies y+5=-\cfrac{4}{5}(x+4) \\\\\\ y+5=-\cfrac{4}{5}x-\cfrac{16}{5}\implies y=-\cfrac{4}{5}x-\cfrac{16}{5}-5\implies y=-\cfrac{4}{5}x-\cfrac{41}{5}

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User Pixelworlds
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