Question

To separate a 0.40 C charge from another charge, 32 J of work is done. What is the voltage of the 0.40 C charge?

Answer 1

80 volt

Step-by-step explanation:

We have given charge = 0.4 C

Work done = 32 J

We have to calculate the voltage required to separate the charge

Work done is equal to the multiplication of charge and voltage that W = charge ×voltage =QV

So
`32=0.4* V`

`V=(32)/(0.4)=80volt`

So 80 volt is required to seprate the two charge of 0.4 C