Question

Electric field due to a point charge inside a dielectric medium (eg, glass, water, etc.): How does the expression for the electric field due to a positive point charge change in the presence of a dielectric medium with relative permittivity &?

Answer 1

Step-by-step explanation:

The electric field due to a positive charge at a distance is given by

`E = (1)/(4\pi \epsilon _(0))(q)/(r^(2))`

Where, q be the charge on the charged particle and r be the distance between the charged particle and the point where electric field is to be calculated.

If the medium is inserted whose dielectric constant is K , then the electric field becomes

`E' = (1)/(4\pi \epsilon _(0)K)(q)/(r^(2))`

As teh value of K is more than 1, so the value of electric field E' is less than E.

It means when the medium is inserted, the electric field becomes reduced.