Question

Write 337,060 in expander form using exponentsd

Answer 1

`337060=(3 *{10}^(5))+(3 * {10}^(4))+(7 * {10}^(3))+(6 *10)`

Explanation:

Writing 337,060 in expanded form we obtain
`337060=300000+30000+7000+ 000+60+0`

But because the value of the digit 0 in 337060 is 0, we can rewrite the expanded form as

`337060= 300000+30000+7000+60`

This can be written as

`337060=(3 *10000)+(3 * 10000)+(7 *1000)+(6 * 10)`

Using the exponent form we obtain

`337060 = (3 * {10}^(5))+(3 * {10}^(4))+(7 * {10}^(3)+(6 *10)`

Therefore the expanded

`337060=(3*{10}^(5))+(3 *{10}^(4))+(7*{10}^(3))+(6*10)`