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The distance d in feet that a dropped object falls in t seconds is given by the equation d divide by 16=t to the second power.How long does it take a dropped object to fall 64 feet?

2 Answers

3 votes

Answer:16+64= 80

Explanation:

answered
User LorneCash
by
8.3k points
2 votes

Explanation:

It is given that, the distance(d) that a dropped object falls in t seconds is given by the following equation as :


(d)/(16)=t^2............(1)

Where

d is the distance (in feet)

t is time (in seconds)

We need to find the time taken by the object to fall 64 feets. Put the value of d = 64 feet in equation (1) as :


(64)/(16)=t^2


t^2=4

t = 2 seconds

So, the object will take 2 seconds to fall 64 feets. Hence, this is the required solution.

answered
User Nicko Glayre
by
8.5k points

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