The Capacitive reactance of a 0.094uF capacitor when a frequency of 25kHz is applied is lus 68 Ohms 0.68 Ohms luf

Question

asked Mar 5, 2020 48.2k views

1 Answer

Rabid · Answer 1 · 2020-03-10T17:05:22+0000

Answer:

Capacitive reactance of the capacitor is 68 ohms

Step-by-step explanation:

It is given that,

Capacitance,
$C=0.094\ \mu F=0.094* 10^(-6)\ F$

Frequency,
$f=25\ kHz=25* 10^3\ Hz$

Capacitive reactance is given by :

$X_C=(1)/(2\pi fC)$

$X_C=(1)/(2\pi 25* 10^3* 0.094* 10^(-6))$

$X_C=67.72\ \Omega$

or

$X_C=68\ \Omega$

So, the capacitive reactance of the capacitor is 68 ohms. Hence, this is the required solution.