Question

To lift a car, you use a hydraulic lift filled with a fluid that has density of 1 1200 kg/m3. The radius of one half of the lift is 0.5 meters and the diameter of the other half of the lift is 2.5 meters. Before you put a mas of 200 kg on the smaller piston, the heights of each piston are the same. If the car weighs 2200 kg, how high will it be raised?

Answer 1

3.8 cm

Step-by-step explanation:

density of fluid = 11200 kg/m^3

r = 0.5 m

R = 2.5 / 2 = 1.25 m

m = 200 kg

f = 200 x 10 = 2000 N

M = 2200 kg

F = 2200 x 10 = 22000 N

a = 3.14 x r^2 = 3.14 x 0.5 x 0.5 = 0.785 m^2

A = 3.14 x R^2 = 3.14 x 1.25 x 1.25 = 4.9 m^2

P1 = f / a = 2000 / 0.785 = 254.77 Pa

P2 = F / A = 22000 / 4.9 = 4489.8 Pa

Let h be the difference in height in both the cylinders

h x density x g = P2 - P1

h x 11200 x 10 = 4489.8 - 254.77

h = 0.038 m = 3.8 cm