Question

What is the equation of the line that is parallel to the given line and passes trough the point (2,3)?

Answer 1

The answer is c

Explanation:

Answer 2

`y=(-1)/(2)x + 4`

Explanation:

First we need to find the slope of the given line, the one that is passing trough the points (-4,0) and (4,-4).

For that, lets use the slope`s equation
`(y_(2)-y_(1))/(x_(2)-x_(1))`

m= (-4-0) / (4-(-4)) = -1/2

A line that is parallel to this one must have its same slope, so m2= -1/2

Now, lets find the 'y' axis intercept point using the point given: (2,3)

And the equation for lines: y=mx+b

By evaluating (2,3) in the above expression we have:

3=-1/2 * 2 +b

From here, we obtain that b=4

Hence, our line is y=-1/2 * x + 4