Question

Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide solution was standardized by titrating 38.87 mL of 0.1994 M standard hydrochloric acid. The initial buret reading of the sodium hydroxide was 1.16 mL, and the final reading was 36.18 mL. What was the molarity of the base solution?

Answer 1

0.221M

Step-by-step explanation:

applying molarity equation

Answer 2

Answer: The molarity of the base solution is 0.22 M.

Step-by-step explanation:

According to the neutralization law,

`n_1M_1V_1=n_2M_2V_2`

where,

`M_1` = molarity of
`HCl` solution = 0.1994 M

`V_1` = volume of
`HCl` solution = 38.87 ml

`M_2` = molarity of
`NaOH` solution = ?

`V_2` = volume of
`NaOH` solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml

`n_1` = valency of
`HCl` = 1

`n_2` = valency of
`NaOH` = 1

`1* 0.1994* 38.87=1* M_2* 35.02`

`M_2=0.22M`

Therefore, the molarity of the base solution is 0.22 M.