Answer: 5) ∠E = 75°, ∠R = 15°, ∠W = 90°
6) An obtuse angle is greater than 90°. If there were 2 angles greater than 90°, then it could not be a triangle because the three angles would be greater than 180° and a triangle has three angles whose sum is 180°
7a) KH, b)KC & CH, c) ∠C, d) ∠K
Explanation:
Since ER is the hypotenuse, then ∠W is the right angle ⇒ ∠W = 90°
E ∠E = 5∠R
|\ ∠E + ∠R = 90°
| \ 5∠R + ∠R = 90°
| \ 6∠R = 90°
| \ ∠R = 15°
| \
W R ∠E = 5∠R
= 5(15°)
= 75°
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Since CK is perpendicular to CH, then ∠C is a right angle ⇒ ∠C = 90°
K
|\ a) the hypotenuse is KH
| \ b) the legs are the perpendicular line segments (CK & CH)
| \ c) see comment above (∠C = 90°)
| \ d) ∠K + ∠H = 90°, therefore they are complimentary ∠s
| \
C H