Question

For an enzyme catalyzed reaction at equilibrium, what is the K if the concentrations of product is 0.5 mM and concentration of substrates are 6.5 mM and 3.0 mM?

a) 3.9x 10
b)2.56 x 10
c) 167
d) 25.6
e) 2560

Answer 1

d) 25.6

Step-by-step explanation:

K = [0.5 e-3]/ [6.5 e-3 x 3.0 e-3]

= 0.0256

= 25.6