Question

A line has a y-intercept at (0,−15) and contains the point (−4,−3). What is the equation of the line in slope-intercept form?

Answer 1

Answer:
`y=-3x-15`

Explanation:

The equation of the line in Slope-Intercept form is:

`y=mx+b`

Where "m" is the slope and "b" the y-intercept.

Since the given line has a y-intercept at (0,-15), then:

`b=-15`

The formula for calculate the slope is:

`m=(y_2-y_1)/(x_2-x_1)`

Knowing that the given line contains the points (0,-15) and (-4,-3), we can calculate the slope. This is:

`m=(-15-(-3))/(0-(-4))=-3`

Substituting values into
`y=mx+b`, we get that the equation of the line in Slope-Intercept form is:

`y=-3x-15`