Question

The volume of a sample of hydrogen gas was decreased from 14.65 L to 7.94 L at constant temperature. If the final pressure exerted by the hydrogen gas sample was 5.02 atm, what pressure did the hydrogen gas exert before its volume was decreased?

Answer 1

The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.

Step-by-step explanation:

Using Boyle's law

`{P_1}* {V_1}={P_2}* {V_2}`

Given ,

V₁ = 14.65 L

V₂ = 7.94 L

P₁ = ?

P₂ = 5.02 atm

Using above equation as:

`{P_1}* {V_1}={P_2}* {V_2}`

`{P_1}* {14.65}={5.02}* {7.94}\ atm`

`{P_1}=\frac {{5.02}* {7.94}}{14.65}\ atm`

`{P_1}=2.7207\ atm`

The pressure the hydrogen gas exerted before its volume was decreased is 2.7207 atm.