Question

Trying to group factor an equation, n^2-3b^2+nb-3n

Can anyone help me understand?

Thank you!

Answer 1

n(n - 3) + b(n - 3b)

Explanation:

n^2 - 3b^2 + nb - 3n =

Rearrange the terms in a way in which you have two terms with a common factor and another two terms with a common factor.

= n^2 - 3n + nb - 3b^2

Now factor a common factor out of each two terms.

= n(n - 3) + b(n - 3b)

Answer 2

`n(n-3)+b(n-3b)`

Explanation:

`n^2-3b^2+nb-3n`

Lets group the terms that has same variables and try to factor

Rearrange the terms

`n^2-3n-3b^2+nb`

Group first two terms and last two terms

`(n^2-3n)+(nb-3b^2)`

Factor out 'n' from the first group and 'b' from the second group

`n(n-3)+b(n-3b)`

Here there is no common factor . So this cannot be factored further