Question

In the accompanying diagram, isosceles triangle ABC has coordinates A(-4,0), B(4,0), C(0,4). Find the area of ABC.

Answer 1

The area of triangle ABC is
`16\ units^(2)`

Explanation:

we know that

The area of a triangle is equal to

`A=(1)/(2)(b)(h)`

In this problem we have

`b=AB=4-(-4)=8\ units` ---> the length of the base b is the difference of the x-coordinates between A and B

`h=OC=4-0=4\ units` ---> the height h is the difference of the y-coordinates between C and the origin O

substitute the values in the formula

`A=(1)/(2)(8)(4)`

`A=16\ units^(2)`