Question

If the length of one leg of a right triangle is 8 and the hypotenuse is √113, what is the length of the other leg?

Answer 1

Explanation:

other leg = √[(√113)² - 8²]

other leg = √[113 - 64]

other leg = √49

other leg = 7 cm

Answer 2

To answer this question you must use Pythagorean theorem

`a^(2) +b^(2)=c^(2)`

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 8

b = unknown

c = √113

^^^Plug these numbers into the theorem

`8^(2) +b^(2) =√113^(2)`

Simplify

64 + b² = 113

solve for x

`b^(2)` = 49

Take the square root of both sides to cancel out the square from the b:

√b² = √49

b = 7

Hope this helped!

~Just a girl in love with Shawn Mendes