Question

A proton, mass 1.67 · 10 27 kg and charge +1.6 · 10 19 C, moves in a circular orbit perpendicular to a uniform magnetic field of 0.71 T. Find the time for the proton to make one complete circular orbit.

Answer 1

Time,
`T=9.23* 10^(-8)\ s`

Step-by-step explanation:

It is given that,

Mass of proton,
`m=1.67* 10^(-27)\ kg`

Charge on proton,
`q=1.6* 10^(-19)`

Magnetic field, B = 0.71 T

Time taken by proton to make one complete circular orbit is given by :

`T=(2\pi m)/(qB)`

`T=(2\pi * 1.67* 10^(-27))/(1.6* 10^(-19)* 0.71)`

`T=9.23* 10^(-8)\ s`

So, the time for the proton to make one complete circular orbit is
`9.23* 10^(-8)\ s`. Hence, this is the required solution.