Question

A solution contains 100.0 g water, 10.0 g NaCl, and 15.0 g methanol. What is the masspercent of methanol in the solution?

Answer 1

12% is the mass percent of methanol in the solution.

Step-by-step explanation:

Mass of water = 100.0 g

Mass of NaCl = 10.0 g

Mass of methanol = 15.0 g

Mass of the solution = 100.0 g+ 10.0 g+ 15.0 g = 125.0 g

`Mass\%=\frac{\text{mass of compound}}{\text{Total mass of solution}}* 100`

`Methanol\%=(15.0 g)/(125.0 g)* 100=12\%`

12% is the mass percent of methanol in the solution.