Question

What is the center and radius of the circle using radicals as needed?

Answer 1

The center is (7,-2)

The radius is
`r=√(37)\ units`

Explanation:

we know that

The equation of the circle in standard form is equal to

`(x-h)^(2)+(y-k)^(2)=r^(2)`

where

(h,k) is the center and r is the radius

in this problem we have

`(x-7)^(2)+(y+2)^(2)=37`

therefore

The center is (7,-2)

The radius is

`r^(2)=37\\ r=√(37)\ units`