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3 votes
A 0.20 M solution of MgSO, has an observed osmotic pressure of 7.6 atm at 25°C. Determine the observed van't Hoff factor i for this experiment a) 1.6 b) 19 c)0.31 d)1.8 e) 2.0

1 Answer

4 votes

Answer: The correct answer is Option a.

Step-by-step explanation:

To calculate the Vant't Hoff factor, we use the equation for osmotic pressure, which is:


\pi=icRT

where,


\pi = osmotic pressure of the solution = 7.6 atm

i = Van't hoff factor = ?

c = concentration of
MgSO_4 = 0.20 mol/L

R = Gas constant =
0.0820\text{ L atm }mol^(-1)K^(-1)

T = temperature of the solution =
25^oC=[273+25]=298K

Putting values in above equation, we get:


7.6atm=i* 0.20mol/L* 0.0820\text{ L.atm }mol^(-1)K^(-1)* 298K\\\\i=1.6

Hence, the correct answer is Option a.

answered
User Nuno Santos
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