Question

What is the molarity of 1.1 mol of sucrose in 3.7 L of solution

Answer 1

• 0.30 M

Step-by-step explanation:

1) Data:

• M = ?

• Solute = sucrpse

• n = 1.1 mol

• V = 3.7 liter

2) Formula:

Molarity is the concentration unit that expresses number of solute moles per liter of solution:

• M = n / V in liter

3) Solution:

• M = 1.1 mol / 3.7 liter = 0.297 mol / liter = 0.297 M

The final answer must be rounded to 2 significant figures, so it is 0.30M