Question

PLEASE HELP!!!!DESPERATE!!! To study the effect of dissolved salt on the rusting of an iron sample, a student prepared a solution of NaCl by dissolving 3.038 g of NaCl in enough

water to make 792.2 mL of solution. What is the molarity of this solution?


C(NaCl)= __________M​

Answer 1

`\boxed{\text{c(NaCl) = 0.065 62 mol/L}}`

Step-by-step explanation:

The formula for molar concentration c is

`c =\frac{\text{moles}}{\text{litres}}\\\text{Moles} = \text{3.038 g} * \frac{\text{1 mol}}{\text{58.44 g}} = \text{0.051 98 mol }\\\\\text{Litres} = \text{792.2 mL} * \frac{\text{1L}}{\text{1000 m&}} = \text{0.7922 L }\\\\c = \frac{\text{0.051 98 mol}}{\text{0.7922 L}} = \text{0.065 62 mol/L }\\\\\text{ The molar concentration of this solution is } \boxed{\textbf{0.065 62 mol/L}}`