Question

Find the missing values in the equation below.

Line 1: 2/3 - 1/2 = 4/?-?/6
Line 2: / - / = ?/6

Answer 1

`(2)/(3) - (1)/(2) = (4)/(6) - (3)/(6)`

`(2)/(3) - (1)/(2) = (1)/(6)`

Explanation:

Given

`(2)/(3) - (1)/(2) = (4)/(?) - (?)/(6)`

`/ - / = (?)/(6)`

Required

Fill in the gaps

For Line 1, convert both fraction to a denominator of 6.

This is shown below:

`(2)/(3) - (1)/(2) = (4)/(?) - (?)/(6)`

`(2)/(2)*(2)/(3) - (1)/(2) *(3)/(3)`

`(2*2)/(2*3) - (1*3)/(2*3)`

`(4)/(6) - (3)/(6)`

Hence:

`(2)/(3) - (1)/(2) = (4)/(6) - (3)/(6)`

For Line 2;

We have:

`(2)/(3) - (1)/(2) = (4)/(6) - (3)/(6)`

`(2)/(3) - (1)/(2) = (4-3)/(6)`

`(2)/(3) - (1)/(2) = (1)/(6)`