Question

An object of mass m is traveling at constant speed v in a circular path of radius r. How much work is done by the centripetal force during one half of a revolution?

Answer 1

Answer:
`W=\pi mv^2`

Step-by-step explanation:

As we know work done is given by

`W=\int_(0)^(\pi r)F.dx`

because we are taking only half a revolution

`F(centripetal force )=(mv^2)/(r)`

`W=(mv^2)/(r)* \pi r`

`W=\pi mv^2`