Question

A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 20 went to right center field, 9 went to center field, 10 went to left center field, and 2 went to left field.

(a) What is the probability that a randomly selected home run was hit to right field?
(b) What is the probability that a randomly selected home run was hit to left field?
(c) Was it unusual for this player to hit a home run to left field? Explain.

Answer 1

a)
`P(E_(1))=(19)/(60)`

b)
`P(E_(2))=(2)/(60)=(1)/(30)`

Explanation:

PROBABILITY OF AN EVENT IS DEFINED AS

`P(E)=(FavourableCases)/(TotalCases)`

a)

Favorable cases for runs being scored on right of field are 19 Thus probability equals

`P(E_(1))=(19)/(60)`

b)

Favorable cases for runs being scored on left of field are 2 Thus probability equals

`P(E_(2))=(2)/(60)=(1)/(30)`

c)

Yes it was unusual for the player to hit a home run to left of the field since his probability of hitting the run towards his left is least among all the other areas in which he scored runs.