Question

Let set C = {even numbers between 1 and 99} and set D = {numbers between 1 and 150 that are evenly divisible by 10}.

What is C ∩ D?

Answer 1

{10, 20, 30, 40, 50, 60, 70, 80, 90}

Explanation:

Answer 2

C ∩ D = {10, 20, 30, 40, 50, 60, 70, 80, 90}

Explanation:

Set C is basically,

C = { 2, 4, 6, 8, 10, .... 92, 94, 96, 98 }

And set D is,

D = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150}

We want to figure out C ∩ D, which means "C intersection D". Intersection means common. So we need to find the numbers that are common to both C and D.

First of all, set D is all even numbers, so we need to find which of the elements in Set D are part of Set C. Since set C's last element is 98, we exclude 100 and above from Set D, hence the element that are common to both sets are 10, 20, 30, 40, 50, 60, 70, 80, and 90.

So, C ∩ D = {10, 20, 30, 40, 50, 60, 70, 80, 90}