Question

Quadrilateral EFGH has coordinates E(2b, 2b), F(3b, b), G(b, o), and H(0, 0). Find the midpoint of HE. Help me!

Answer 1

according to the picture, it would be the 4th choice

Answer 2

`(b,b)`

Explanation:

To get the result you can use the formula for the midpoint between two points, given by

`\left ((x_1 + x_2)/(2), (y_1+y_2)/(2)\right )`

where
`(x_1,y_1)` and
`(x_2,y_2)` are the two points.

So, replace the points
`(x_1,y_1)=(0,0)` and
`(x_2,y_2)=(2b,2b)` as follows:

`\left( (0+2b)/(2),(0+2b)/(2)\right ) = \left( (2b)/(2),(2b)/(2) \right)=\left( b,b\right)`

Therfore the midpoint of HE is
`(b,b)`