Question

Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)

Answer 1

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A = 0.29 J

`\mu =3716.35 J/mole`

Step-by-step explanation:

given data:

Kr atomic number = 36

degree of freedom = 3

1) internal energy E =
`(f)/(2) n R T`

=
`(3)/(2) *1*8.314*298 = 3716.35 j`

2)
`cv = (E)/(T)`

`= (3716.35)/(298) = 12.47 J/K`

3)
`S = cv =(E)/(T) = 12.47 J/K`

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)
`chemcial potential \mu = (energy)/(mole) = 3716.35 J/mole`