Question

Calculate the impedance (magnitude, phase angle) of a RC series circuit (R = 10 kOhm, C = 0.2 muF) at frequency f= 150 Hz.

Answer 1

impedance for RC series = 11,320.102Ω

Φ = 27.92°

Step-by-step explanation:

Given,

R = 10 KΩ = 10 × 10³ = 10⁴ Ω

C = 0.2 μF = 0.2 × 10⁻⁶ F

frequency = 150 Hz

ω = 2πf = 2π × 150 = 300π

ωC = 300π × 2 × 10⁻⁷ = 6π × 10⁻⁵

1/ωC = 5305.16

impedance for RC series =

`\sqrt{\omega^2+(1)/(\omega^2C^2)}\\√(10^8 + 28,144,722.6)\\11,320.102 \Omega \\`

phase angle=

`\phi = tan^(-1)(((1)/(\omega C))/(R)) = tan^(-1)((5305.16)/(10^4)) = tan^(-1)(0.5304)=27.92^(\circ)`