Question

Find the distance between the points (-3, -2) and (-1, -2).

Answer 1

The distance is,

`d(A,B)=√((x_2-x_1)^2+(y_2-y_1)^2)`

Where
`A(x_1,y_1),B(x_2,y_2)\longrightarrow A(-3,-2),B(-1,-2)`

`d(A,B)=√((-1-(-3))^2+(-2-(-2))^2)=√(4)=2`

The distance between points A, B is 2 units.

Hope this helps.

r3t40

Answer 2

The formula for distance between two points is:

`\sqrt{(x_(2) -x_(1))^(2) + (y_(2) -y_(1))^(2)}`

In this case:

`x_(2) =-1\\x_(1) =-3\\y_(2) =-2\\y_(1) =-2`

^^^Plug these numbers into the formula for distance like so...

`\sqrt{(-1 - (-3))^(2) + (-2 - (-2))^(2)}`

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

`\sqrt{(-1 - (-3))^(2) + (-2 - (-2))^(2)}`

-1 - (-3) = 2

`\sqrt{(2)^(2) + (-2 - (-2))^(2)}`

-2 - (-2) = 0

`\sqrt{(2)^(2) + (0)^(2)}`

Next solve the exponent. Again, you must do this from left to right

`\sqrt{(2)^(2) + (0)^(2)}`

2² = 4

`\sqrt{4 + (0)^(2)}`

0² = 0

`√((4+0))`

Now for the addition

`√((4 + 0))`

4 + 0 = 4

√4 <<<This can be further simplified to...

2

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes