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How many moles of iodine are in 0.333 mol of CaO(I03)2 ?

1 Answer

1 vote

Answer:

0.666 mol I

Step-by-step explanation:

0.333 mol CaO(IO₃)₂ × (2 mol IO₃ / mol CaO(IO₃)₂) = 0.666 mol IO₃

0.666 mol IO₃ × (1 mol I / mol IO₃) = 0.666 mol I

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User Mpavlov
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