Question

Find the zero of y=x^2-6x-4 by completing the square

Answer 1

x = 3 + √13

I just got this answer on AP3X and it was the correct answer!

Answer 2

x = 3 + √13, 3 - √13 or

6.61, -0.61 to the nearest hundredth.

Explanation:

y = x^2 - 6x - 4

x^2 - 6x - 4 = 0

(x - 3)^2 - 9 - 4 = 0

(x - 3)^2 = 13

x - 3 = +/- √13

x = 3 + √13, 3 - √13.