Question

The expression (27y^-2)^1/3 / y^-2/3 can be simplified and written without negative exponents as

Answer 1

3

Explanation:

`\displaystyle\tt \frac{(27y^(-2))^{(1)/(3)}}{y^{-(2)/(3)}}=\frac{(3^3\cdot y^(-2))^{(1)/(3)}}{y^{-(2)/(3)}}=\frac{3\cdot y^{-(2)/(3)}}{y^{-(2)/(3)}}=3`