Question

I am equation of the line that passes through the point (2,3) with slope 3 please answer

Answer 1

y-3 = 3(x-2) point slope form

y = 3x-3 slope intercept form

Explanation:

We can use the point slope form of the equation for a line

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is the point

y-3 = 3(x-2) point slope form

If we want the line in slope intercept form

Distribute

y-3 = 3x-6

Add 3 to each side

y-3+3 = 3x-6+3

y = 3x-3 slope intercept form

Answer 2

`\huge{\boxed{y-3=m(x-2)}}`

Point-slope form is
`y-y_1=m(x-x_1)`, where
`m` is the slope and
`(x_1, y_1)` is a point on the line.

Substitute the values.
`\boxed{y-3=m(x-2)}`

Note: This is in point-slope form. Let me know if you need a different form. Also, if you have any more problems similar to this, I encourage you to try them on your own, and ask on here if you are having trouble.