What is the equation of a circle with a center (1, -4) and raidus 2?

Question

asked Dec 15, 2020 129k views

1 Answer

Mohamed Abouelnasr · Answer 1 · 2020-12-19T09:00:55+0000

Answer:

(x-1)^2 + (y+4)^2=2^2

Explanation:

The equation of a circle is given by:

(x-a)^2 + (y-b)^2 = r^2

Where the center is (a,b) and the radius is r

Since center (1, -4), we can say :

$(x-a)^2 + (y-b)^2\\(x-1)^2 + (y+4)^2$

The right side would be
2^2

So the equation woud be:
(x-1)^2 + (y+4)^2=2^2

This is the equation of the circle, posted.