Question

A ten loop coil of area 0.23 m2 is in a 0.047 T uniform magnetic field oriented so that the maximum flux goes through the coil. The coil is then rotated so that the flux through it goes to zero in 0.34 s. The average emf induced in the coil during the 0.34 s is:

Answer 1

0.32 V

Step-by-step explanation:

N = 10, A = 0.23 m^2, B = 0.47 T, t = 0.34 s

The average induced emf is given by

e = - N dФ / dt

Where, dФ be the change in magnetic flux in time dt.

dФ / dt = d / dt (B A) = A dB/dt

So,

e = - 10 x 0.23 x 0.047 / 0.34 = - 0.32 V

The negative sign shows the direction of induced emf.